I have a for loop that counts up by 1 to a number. This number on each iteration is plugged into a matrix and a column vector of answers is outputted:
% constants:
R1 = 3000 ;R2 = 8000 ;R4 = 2000 ;R5 = 4000 ;% R3 = 2130 ; <--- this should be the answer for "r" below
v = 110 ; for r = 2000:3000R3 = r;A = [0 -R2 0 -R4 0 0 % the "A" matrix
R1 -R2 R3 0 0 0 0 0 -R3 -R4 R5 0 -1 -1 0 0 0 1 0 1 1 -1 0 0 1 0 -1 0 -1 0 0 0 0 1 1 -1];b = [-v; 0; 0; 0; 0; 0; 0];x = A\b ; % the answer column vector
if x(4) == 0.0170 answer = r breakendend
In this code, "x" is a column vector. I want to terminate the for-loop when the "r" index causes the fourth row in x to be equal to 0.0170.
I know that the index value should be 2130, (in other words, I already know the answer) but the code doesn't "break" when this condition is met. Instead,
the for-loop keeps counting to whichever bound I told it to end at (in this case, 3000).
I'm sure I'm missing something simple here but I can't find what it is. Any help would be greatly appreciated!
Best Answer