MATLAB: For loop for a function

Question

I have the following function and I want to run it for age 30 to 100. I think I need to develop a for loop here. Can anyone please help me out? I know if I change the value of age step by step like 30, 31 …. then I can do it but I need to run it as a for loop

function hf = myfun(age)
age = [30:100]
hf = zeros(5,5);
hf(1,2) = exp(-0.0625.*age-0.0134); % exp(age effect+time effect) 
hf(1,5) = exp(-9.65573+0.01844+0.08218*age+0.02246); % exp(intercept+ age effect+time effect) 

hf(2,3) = exp(-1.6660-0.1116.*age-0.0025); % exp(intercept+ age effect+time effect) 
hf(2,4) = exp(-8.96236+0.07691.*age + 0.00978); % assuming the death rate of male of same age(Hubener et al.)
hf(2,5) = exp(-9.65573+0.08218.*age+0.02246); % self-mortality 
hf(3,2) = exp(-0.0625.*age-0.0134+0.0676); %exp(intercept+ age effect+time effect+marriage once before)
hf(3,5) = exp(-9.65573+0.08218.*age+0.02246-0.11853);
hf(4,2) = exp(-0.4176-0.0625-0.0134.*age);
hf(4,5) = exp(-9.65573+0.08218.*age+0.02246-0.00415);
hf(1,1) = -(hf(1,2)+hf(1,5))
hf(2,2) = -(hf(2,3)+hf(2,4)+hf(2,5))
hf(3,3) = -(hf(3,2)+hf(3,5))
hf(4,4) = -(hf(4,2)+hf(4,5))
end

Answer 1

You construct the for loop like this:

for i=1:size(age,2) %by referencing your age array, you can change the age values and it will still work
    hf(i,:,:) = zeros(5,5);
    hf(i,1,2) = exp(-0.0625.*age(i)-0.0134);  %index every step of hf to rely on i, and use the i'th value of age for the evaluations of the whole way
end

In the end, you will have hf(1,:,:) contain your results from age(1) in this case age=30, hf(2,:,:) age = 31 and so on.