% set domains limits and boundary conditions
xo = pi/2; xf = pi; yxo = 1; yxf = 1; N = 10;% compute interval size and discrete x vector
dx = (xf-xo)/N; dx2 = dx*dx; x = (xo+dx):dx:xf; % analytica solution (exact)
xe = linspace(xo,xf,N); ye = (pi./(2*xe)).*(sin(xe) - 2*cos(xe)); % arranging the matrix a
%node 1
a(1,1)=dx2-2; a(1,2)=1+(dx/(xo+dx)); b(1)= ((yxo*dx) /(xo*dx))-yxo; for i = 2:N-1 a(i,i-1) = (1-(dx/x(i))); a(i,i) = dx2-2; a(i,i+1) = (1+(dx/x(i))); b(i)=0; end a(N,N-1)=(2*xf+2*dx)/xf; a(N,N-2)=-1; b(N)=yxf*dx2+yxf+((2*yxf*dx)/xf); yi=a\b;
i keep getting the following error code
finite_1
Error using \
Matrix dimensions must agree.
Error in finite_1 (line 26)
yi=a\b
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