Hi, I want to find in each loop for L, the maximum value of SP and corresponding p value. That means, I want the results to be two vectors of length numel(L).
I know that findpeaks could help to identify the maximum and its location, but i always got the error message "In an assignment A(:) = B, the number of elements in A and B must be the same. Error in optimalp(j) = prange(locs);"
Could anyone help me to fix this? Or is there any other methods to output the maximum of SP and corresponding p values? Because i want to use the vectors to plot the graph later.
THANKS!!!
L = 0.01:0.01:1;p = 0:0.01:1; optimalp = zeros(1,numel(L));maximum = zeros(1,numel(L));SP = zeros(1,numel(p));for j = 1:numel(L) for i = 1:numel(p) if Lambda(j) >= mu if p(i) < R-c^2/(mu*phi) SP(i) = p(i)*(mu-c/(R-p(i))); else SP(i) = p(i)*(mu-sqrt(mu*phi/(R-p(i)))); end else SP(i) = p(i)*L(j); end end [pks,locs]=findpeaks(SP); optimalp(j) = p(locs); end
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