If I have performed a cubic interp to some data,
x = linspace(1,maxFwhm+1,maxFwhm+1)'f=fit(x,y,'cubicinterp')hold onplot(f,'k--')coeffvalues(f)
How can I now calculate the x value that corresponds with the y value of 0.5?
Thanks Jason
cubicinterpCurve Fitting Toolboxfit
x = linspace(1,maxFwhm+1,maxFwhm+1)'f=fit(x,y,'cubicinterp')hold onplot(f,'k--')coeffvalues(f)
Best Answer