MATLAB: Find the vertices from delaunay triangulation

Question

i creates a Delaunay triangulation using the following lines

X = [y(:,1) x(:,1)];
dt = delaunayTriangulation(X);

The output "dt" is a matrix with 3 columns (a,b,c). How can i find the vertices of the triangles so that i get (xa,ya) (xb,yb) and (xc,yc)

Answer 1

x = rand(10,1) ; % a randoms data 
y = rand(10,1) ;
dt = delaunayTriangulation(x,y) ;   % delaunay triangulation 
points = dt.Points ;    % points 
tri = dt.ConnectivityList ;    % nodal connectivity 
x = points(:,1) ;  
X = x(tri) ;
y = points(:,2) ;
Y = y(tri) ;