MATLAB: Find the column with the least number of 1s (ones) in it | Find column with at least one non zero element

columnelementinvertmatrixmovenon-zeropermutationrowshift

Consider I have a m by n matrix with binary data
Is there a easy way to write a code that can identify the column with the least number of ones in them.
My current code identifies the column with zero 1s, which is not what I seek
H = [0 0 1 1 0 1 0 1 0 1 1 0;
     0 0 0 1 0 1 1 0 1 0 1 0;
     0 1 1 0 0 1 1 1 0 0 0 1;
     0 1 1 0 1 0 1 0 1 0 0 0;
     0 0 0 1 1 0 0 1 1 0 0 0;
     0 1 0 0 1 0 0 0 0 0 1 1];
%For ex, here the column with least number of ones is column 10.
%whereas column 1 has all zero elements which is not the result I want.
%This is my code which gives wrong results
 a = sum(H);
amax = max(a);
amin = min(a);

Best Answer

count = sum(H);
idx = find(count);
[~, relidx] = min(count(idx)) ;
mincol = idx(relidx);
Related Question