MATLAB: Find length NaN segments

nan segments

I have large vectors, containing quite a lot of NaN samples. I want to know the length of each array of NaNs within this vector, even when this equals 1. So I want to have the lenght of all NaN segments.

Thanks in advance!

Best Answer

https://www.mathworks.com/matlabcentral/answers/444595-count-the-occurence-of-a-number-in-between-other-numbers - replace the first line with isnan().

Related Solutions

MATLAB: How to find the indices of NaN values in a cell array

Try this:

D = load('XTrain2_all.mat');
XTrain2_all = D.XTrain2_all;
hasNaN = cellfun(@nnz,cellfun(@isnan, XTrain2_all, 'Unif',0), 'Unif',0);    % Cells With ‘NaN’ Values
idx = find([hasNaN{:}]);                                                    % Their Indices
XTrain2_all(idx) = XTrain2_all(idx-1);                                      % Replace With Previous
hasNaN = cellfun(@nnz,cellfun(@isnan, XTrain2_all, 'Unif',0), 'Unif',0);    % Check

Check = find([hasNaN{:}]);                                                  % Check

MATLAB: Count the occurence of a number in between other numbers

This is simpler and actually works for all horizontal vectors (unlike the accepted answer):

>> x = [ 1 0 0 1 1 1 0 1 1 0 0 0 0 0 1 1 0 1 0];
>> D = diff([false,x==0,false]);
>> find(D<0)-find(D>0)
ans =
     2     1     5     1     1

For a slightly faster version you can call find once:

>> F = find(diff([false,x==0,false]));
>> F(2:2:end)-F(1:2:end)
ans =
     2     1     5     1     1

EDIT: uses Jan's logical vector suggestion.

Best Answer

Related Solutions

MATLAB: How to find the indices of NaN values in a cell array

MATLAB: Count the occurence of a number in between other numbers

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