MATLAB: Find angle in a open curve

angle finding

in image step wise I show the wanted result…. But i am new in matlab in have no coding expernce so plz help me….

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Let P1, P2,P3 be three points....with P2 in middle....get two vectors and use the formula given in this link: https://in.mathworks.com/matlabcentral/answers/101590-how-can-i-determine-the-angle-between-two-vectors-in-matlab

u = P2-P1 ;
v = P2-P3 ;

Related Solutions

MATLAB: How to use the three points A1, A2, and B0 to calculate ∠A1B0A2

A1 = [171 422] ;
A2 = [415 413] ;
B0 = [277 386] ;
d1 = A1-B0 ;
d2 = A2-B0 ;
theta = atan((d2(2)-d1(2))/(d2(1)-d1(1)))

MATLAB: Explicit root of symbolic equations

syms d1 d2 d3 d4 d5 d6 h11 h12 h13 h14 h21 h22 h23 h24 h41 h42...
    h45 h46 h51 h52 h55 h56 h61 h62 h65 h66
eq1 = h11*d1+h12*d2+h13*d3+h14*d4 == 0;
eq2 = h21*d1+h22*d2+h23*d3+h23*d4 == 0;
eq3 = d1+d2+d3+d4-d5-d6 == 0;
eq4 = h41*d1+h42*d2-h41*d3-h42*d4-h45*d5-h46*d6 == 0;
eq5 = h51*d1+h52*d2+h51*d3+h52*d4-h55*d5-h56*d6 == 0;
eq6 = h61*d1+h62*d2-h61*d3-h62*d4-h65*d5-h66*d6 == 0;
% Solve for d1...d6
sol_d1 = isolate(eq1,d1)
sol_d2 = isolate(eq2,d2)
sol_d3 = isolate(eq3,d3)
sol_d4 = isolate(eq4,d4)
sol_d5 = isolate(eq5,d5)
sol_d6 = isolate(eq6,d6)

gives:

sol_d1 =
 
d1 == -(d2*h12 + d3*h13 + d4*h14)/h11
 
 
sol_d2 =
 
d2 == -(d1*h21 + d3*h23 + d4*h23)/h22
 
 
sol_d3 =
 
d3 == d5 - d2 - d4 - d1 + d6
 
 
sol_d4 =
 
d4 == -(d3*h41 - d2*h42 - d1*h41 + d5*h45 + d6*h46)/h42
 
 
sol_d5 =
 
d5 == (d1*h51 + d2*h52 + d3*h51 + d4*h52 - d6*h56)/h55
 
 
sol_d6 =
 
d6 == -(d3*h61 - d2*h62 - d1*h61 + d4*h62 + d5*h65)/h66

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Related Solutions

MATLAB: How to use the three points A1, A2, and B0 to calculate ∠A1B0A2

MATLAB: Explicit root of symbolic equations

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