MATLAB: Find a digit in string

strings

i have a folder named "inputImages" it contains 5 images named image1, image2 … image5

i have a variable which contains a digit… if that digit contains in any of the names i want that image to get displayed in a figure…

example

variable=2; then image2.jpg should get displayed….

please can someone help me how to get the name of the image that contains the digit….

Best Answer

 name=['image' num2str(variable) '.jpg'],

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MATLAB: Displaying images by using a variable

It can be done but less ideal.

a=input('enter the number','s');
file=[a,'.jpg'];
imshow(file);

Better

file=uigetfile('select a file');
imshow(file);

MATLAB: What is wrong with the following piece of code? Im trying to detect light and dark green vegetation. It just displays a black empty image

Your Image1 has been produced by im2double() so the range of Image1 is 0 to 1. But your second set of code has

Green = Image1 (i, j, 2) + 20;

so Green is going to be in the range (20+0) to (20+1), which is always going to be greater than the 0 to 1 entries already in Image1, so your "if" is always going to be true.

Note that your second block of code, involving "Green" is going to completely overwrite the output of the first block of code. Your first block might as well not be there.

Your first block could be rewritten without loops as

mask = Image1(:,:,2) > Image1(:,:,1) & Image1(:,:,2) > Image1(:,:,3);
Image2 = Image1 .* mask(:,:,[1 1 1]);

and your second block could be rewritten without loops as

mask = Image1(:,:,2) + 20 > Image1(:,:,1) & Image1(:,:,2) + 20 > Image1(:,:,3);
Image2 = Image1 .* mask(:,:,[1 1 1]);

Best Answer

Related Solutions

MATLAB: Displaying images by using a variable

MATLAB: What is wrong with the following piece of code? Im trying to detect light and dark green vegetation. It just displays a black empty image

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