One might have:
dt = desc: (none) freq: Daily (1) 'dates: (2715)' 'times: (2715)' 'Open: (2715)' 'High: (2715)' 'Low: (2715)' 'Close: (2715)' 'Vol: (2715)' 'OI: (2715)' '19-Mar-2006' '22:00' [ 1164.25] [ 1186.5] [ 1160.5] [ 1183.75] [ 1149131] [ 1064369]
With both a dates and a times column … to remove the times column one could think of:
dt_Close = fints(dt.dates, fts2mat(dt.Close))
This removes the times but gives only one column back … I'd like to keep all columns and remove only the "times" column. So:
Is column indexing by column position (instead of column name) possible? This can be done for rows as:
dt([1 2 3]) % get only first 3 rows
dt([1 3:end]) % skip row 2
as described in another post here …. how can this be done for columns?
Best Answer