MATLAB: Execute matrix in a “for loop”

for looploop through matrix

I have matrix m that is (2000×5)(rowsxcolumns), and I have a code. I want to execute my code for each column of this matrix, i.e.

loop number #1 = m(2000,col1); #2 = m(2000,col2), ……. #5 = m(2000,col5). Does anybody know how to do that?

Best Answer

Let's say your function is foo, you can do

for ii = 1:size(m,2)
    y = foo(m(:,ii));
end

HTH

Related Solutions

MATLAB: Storing data for “for loop”

Try something like this:

L0 = [1 2 3 4 5];
L10 = [2 3 4 5 6];
L20 = [0 9 2 3 4];
L = [L0; L10; L20];
x = 0:4;
n = size(L,2)-2;
for k = 1:size(L,1)
    p(k,:) = polyfit(x,L(k,:),n);
end

This creates a matrix of row vectors in ‘L’. Note that I set ‘n’ to be 2 less than the vector lengths. A 6-order polynomial might be appropriate for your actual data, although it will crash here. (Please re-consider fitting a 6-order polynomial anyway.)

MATLAB: Nested For Loop for 2D Matrix

So then you want to extract random 51x51 submatrices? If so, then,

I=sort(randperm(600,51));
J=sort(randperm(1000,51));
submatrix= matrix(I,J);

Best Answer

Related Solutions

MATLAB: Storing data for “for loop”

MATLAB: Nested For Loop for 2D Matrix

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