MATLAB: “Error: not enough input arguments” even though all input arguments are in workspace.

functionmatlab functionsyntaxtaylor series

I use the function below and I have all input arguments in the workspace (f as function, x, y). It asks me to define f, x, and y when I press run and when I fill these in it works. This really irritates me!! Thanks in advance.

function [G] = TaylorSeries(f, x, y)
syms x y
G = f;
display(G)
end

Best Answer

When you run a function, MATLAB never looks inside the workspace of the place it was invoked from in order to try to locate variables whose names just happen to match the name of the parameter given in the function definition. You always have to pass the values into the function, such as going to the command line and invoking

f = @(x, y) sin(x) - 2*cos(2*y) + tan(x.*y);
x = 1.234;
y = 8.765;
TaylorSeries(f, x, y)

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I think this is what they meant -

In the function file:

function outputVar = myfunction(inputVar)
% write the rest of the program here, using inputVar as you would a string

When you call the function you give it a string:

thisoutput = myfunction('data1.txt')

MATLAB: Function with double arguments

You want to call a MATLAB function an argument that is itself a function, right? You can do that as follows. Define your function like this:

function [g] = forward(f,x)
      for j=5:5:40;
         h = inv(j);
         g = (f(x)+4*f(h)-f(h+h))/(h+h);
      end
end

and call it using a "function handle" like this:

forward(@sin,7) % Argument is the MATLAB built-in sine function

or like this

my_func = @(x) x^2; % Define your own function, and assign its handle
forward(my_func,7) % Argument is function defined by you

Best Answer

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