MATLAB: Error in unziping files and then deleting files in the zip

deleteforloop

Hello,

I have this following code for choosing a folder then deleting some files in specific size

files = fullfile(matlabroot, '\toolbox');
if ~exist(files, 'dir')
	files = matlabroot;
end
uiwait(msgbox('Pick a folder on the next window that will come up.'));
selpath = uigetdir(files);
if selpath == 0
	return;
end
unzip(selpath)
files = dir(selpath);
deletedfiles = 0;
for itr = 1:length(files)
    if files(itr).bytes<200000 && ~files(itr).isdir 
        files.name
        delete(fullfile(files(itr).folder, files(itr).name))
        deletedfiles=deletedfiles+1;
    end
end
deletedfiles

But i got error in the unziping part.

>> cobacoba
Error using parseUnArchiveInputs (line 76)
ZIPFILENAME "D:\Nenen" is a directory.
Error in unzip (line 55)
[zipFilename, outputDir, url, urlFilename] = parseUnArchiveInputs( ...
Error in cobacoba (line 10)
unzip(selpath)

Any ideas what should I do?

Best Answer

As its documentation clearly states, unzip's first input argument needs to be the name of a zip file.

selpath is not the name of a zip file.

Related Solutions

MATLAB: Error in unziping files loop

You need to include the path in the filenames otherwise MATKAB does not know where to find those files, e.g.:

unzip(fullfile(dinfo(K).folder,dinfo(K).name),...);

You should also use numel, not length:

for K = 1:numel(dinfo)

I would regard any code that uses length as inherently buggy. This is a good example. Read the dir and length documentation and then think of what length returns when no files are returned by dir. Test it yourself.

Instead of buggy length you should use numel or size (requesting a specific dimension).

"Any ideas what should I do?"

Use whos and which to check if you have a variable defined named unzip.

MATLAB: Renaming Files After Unzip

files = fullfile(matlabroot, '\toolbox');

So files is a character vector at that point.

files = dir(projectdir);

Eventually you assign the result of dir() over top of the character vector. But before that, it is a character vector.

[~, f] = fileparts(files(id).name);

And that line is before you assign the result of dir() to files

unzip(fullfile(dinfo(K).folder,dinfo(K).name),selpath);

That tells unzip to write the files into the directory indicated by selpath, which is not likely to be the current directory.

[~, f] = fileparts(files(id).name);

If you were to replace files with a variable that you had assigned the results of a dir() call into, then that line in itself would potentially be valid. It is completely valid to use fileparts() on a character vector that refers to a file that is not in the current directory.

movefile(files(id).name, rf);

If you were to replace files with a variable etc., etc., then the line would still need work.That line requires that the given file is located in the current directory, which will not be the case -- the file is over in selpath

Best Answer

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MATLAB: Error in unziping files loop

MATLAB: Renaming Files After Unzip

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