Hi all
I want to compute erfc(.) of a complex number. How can I do that? Is there any way to use erfc(.) of matlab?
MATLAB: Erfc with complex number
complex numbererfc
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On my system, Maple ran out of memory trying to solve() that equation. There is a possibility that a system with more memory might be able to arrive at an answer, given enough time.
Solving the entire system of 12 equations when they are each this large, would take a lot of time and memory.
I would recommend following John's advice to simplify the system.
Hi Harekrishna Mandal
Although MATLAB standard functions erf and erfc only work with real inputs, there is the MATLAB implementation of erfc(z) z Complex, by S. Abrarov, available here
fadf.m Attached to this answer for convenience.
I reach the following plots for a time interval of [0 10] dt=0.01 and sample theta=1
clear all;close all;clc;M=.4;w=pi/2;dt=0.01;t1=0;t2=10;t=[t1:dt:t2]; theta=1; % sample value
p7_1=.25*exp(-1j*w*t)*exp(theta*(M-1j*w)^.5).*fadf((M-1j*w).^.5+.5*theta./(t).^.5);p7_2=.25*exp(-1j*w*t)*exp(-theta*(M-1j*w)^.5).*fadf(-(M-1j*w).^.5+.5*theta./(t).^.5);p7_3=.25*exp(1j*w*t)*exp(theta*(M+1j*w)^.5).*fadf((M+1j*w).^.5+.5*theta./(t).^.5);p7_4=.25*exp(1j*w*t)*exp(-theta*(M+1j*w)^.5).*fadf(-(M+1j*w).^.5+.5*theta./(t).^.5);p7=p7_1+p7_2+p7_3+p7_4;abs_p7=abs(p7);arg_p7=angle(p7);re_p7=real(p7);im_p7=imag(p7);figure(1);plot(t,abs_p7,t,arg_p7);grid on;legend('|p7|','ang(p7)');figure(2);plot(t,re_p7,t,im_p7);grid on;legend('re(p7)','im(p7)');.
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John BG
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