MATLAB: Equation syntax problem. Can someone help me type it in correctly

equationequation entrysyntax

I'm pretty new to matlab and i'm not positive how to type this equation in correctly,

function [E_theta] = example_pattern_function(theta_radians, phi_radians)
E_theta = sin(theta_radians).*sin(cos(theta_radians)*3.14159);
E_theta = E_theta / (3.14159*cos(theta_radians));

any suggestions?

Best Answer

(sin(theta) .* sin(pi * cos(theta)) ./ (pi * cos(theta))).^2

Related Solutions

MATLAB: Solving non linear equation using fsolve

You are not passing theta_n and other parameters to root2d(). One fix is to make root2d a Nested Function. Also, you must choose a different initial point. phi0 = [10,10] worked for me.

function solve_it()
    beta_a = 10;
    alpha_n = 10 ;
    eta= 18;
    i = 18;
    theta_i = 10;
    theta_n = 10 ;
    
    fun = @root2d;
    phi0 = [10,10];
    phi = fsolve(fun,phi0);
    phi_n = phi(1),
    phi_i = phi(2),
    function F = root2d(phi)
    F = zeros(2,1);
    F(1) = (pi*sin((pi*(phi(1) + theta_n))/180)*cos((pi*phi(2))/180)*(cos((pi*theta_n)/180) + tan((pi*i)/180)*tan((pi*theta_i)/180)))/(180*sin((pi*phi(1))/180)*(cos((pi*(phi(1) + theta_n))/180)*cos((phi(2)*pi)/180) + sin((phi(2)*pi)/180)*tan((theta_i*pi)/180))^2) - (pi*cos((pi*phi(1))/180)*(cos((pi*theta_n)/180) + tan((pi*i)/180)*tan((pi*theta_i)/180)))/(180*sin((phi(1)*pi)/180)^2*(cos((pi*(phi(1) + theta_n))/180)*cos((pi*phi(2))/180) + sin((pi*phi(2))/180)*tan((pi*theta_i)/180)));
    F(2) = ((cos((pi*theta_n)/180) + tan((pi*i)/180)*tan((pi*theta_i)/180))*((pi*cos((pi*(phi(1) + theta_n))/180)*sin((pi*phi(2))/180))/180 - (pi*cos((pi*phi(2))/180)*tan((pi*theta_i)/180))/180))/(sin((pi*phi(1))/180)*(cos((pi*(phi(1) + theta_n))/180)*cos((phi(2)*pi)/180) + sin((phi(2)*pi)/180)*tan((theta_i*pi)/180))^2);
    end
end

MATLAB: Strange behavior of diff function with symbolic variables

Hi,

Your expression, D contains only 2 theta1 terms(in bold) whose derivatives cancel each other. Differentiation of theta2 and theta3 wrt theta1 is zero. Therefore your answer is zero.

D =0.31*cos(theta1)^2 - 2.7e-4*sin(theta2) - 0.88*sin(theta2)*(7.3e-5*cos(theta2) - 0.011*sin(theta2) + 3.1e-4) - 0.88*cos(theta2)*(7.3e-5*sin(theta2) - 4.2e-3*cos(theta2) + 4.6e-4) - 1.0*(0.48*sin(theta3) - 0.88*cos(theta2)*cos(theta3))*(5.1e-4*cos(theta3) - 1.7e-4*sin(theta2) - 0.047*sin(theta3) + 0.088*cos(theta2)*cos(theta3) + 9.5e-4*cos(theta2)*sin(theta3)) - 4.1e-4*cos(theta2) + 0.88*sin(theta2)*(3.2e-4*cos(theta3) + 0.073*sin(theta2) + 9.0e-5*sin(theta3) - 1.7e-4*cos(theta2)*cos(theta3) + 5.9e-4*cos(theta2)*sin(theta3)) + 0.31*sin(theta1)^2 + 1.0*(0.48*cos(theta3) + 0.88*cos(theta2)*sin(theta3))*(0.035*cos(theta3) + 5.9e-4*sin(theta2) - 5.1e-4*sin(theta3) + 9.5e-4*cos(theta2)*cos(theta3) + 0.064*cos(theta2)*sin(theta3)) + 0.33;

I hope I could help.

Regards

Best Answer

Related Solutions

MATLAB: Solving non linear equation using fsolve

MATLAB: Strange behavior of diff function with symbolic variables

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