MATLAB: Easier method to iterative matrix multiplication

iterationMATLABmatrix multipication

    n = 10
    matrix = zeros(n,n);
    matrix(1,1:n) = 2 
    matrix1 = zeros(n,n);
    matrix1(1:n,1) = 4
    
    for i = (1:n)
        matrix(i+1,1:n) = matrix(i,1:n)*matrix1;   
    end
    matrix
Outputs:
matrix =
     2     2     2     2     2     2     2     2     2     2
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     0
matrix1 =
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
     4     0     0     0     0     0     0     0     0     0
    
 matrix =
           2           2           2           2           2           2           2           2           2           2
          80           0           0           0           0           0           0           0           0           0
         320           0           0           0           0           0           0           0           0           0
        1280           0           0           0           0           0           0           0           0           0
        5120           0           0           0           0           0           0           0           0           0
       20480           0           0           0           0           0           0           0           0           0
       81920           0           0           0           0           0           0           0           0           0
      327680           0           0           0           0           0           0           0           0           0
     1310720           0           0           0           0           0           0           0           0           0
     5242880           0           0           0           0           0           0           0           0           0
    20971520           0           0           0           0           0           0           0           0           0
The point is that matrix will have more values added to it. matrix 1 will be filled with many different values. I'm trying to find an easier way than a for loop.
matrix1 is made to be that way for easier explanation

Best Answer

No, a loop is the best way.
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