MATLAB: Divide histogram in three parts

MATLAB

Hi, I want to divide the histogram in three parts and define the ranges of three parts.

minRed = min(red(:));
maxRed = max(red(:));
AvgRed = (minRed+maxRed)/3;
AvgRed2 = AvgRed+AvgRed;

But sometimes the value of AvgRed becomes less than minRed and value of AvgRed2 exceeds the maxRed. What is the correct way to do this?

Best Answer

A + (B - A) /3 
A + (B - A) /3 *2

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MATLAB: I did some changes in red,green,blue channel of the image .Now when is am using cat function it is giving me full white image.This is not the output i want

You have white image because of format. Try

imshow(uint8(new_img));

your code can be shorter (no for loop needed)

image=imread('732_img_.png');
[m,n,~] = size(image);
Red=image(:,:,1);
Green=image(:,:,2);
Blue=image(:,:,3);
red_avg = mean(Red(:));
green_avg = mean(Green(:));
blue_avg = mean(Blue(:));
avg = mean(image(:));
disp(red_avg);
disp(green_avg);
disp(blue_avg);
disp(avg);
new_red = avg/red_avg*Red;
new_green = avg/green_avg*Green;
new_blue = avg/blue_avg*Blue;
new_img=cat(3,new_red,new_green,new_blue);
imshow([image new_img])

MATLAB: Bsxfun – @minus – how to divide by maximum

Do do poor job to explain, up to everyone guess

>> a = [3; 5; 1;]
a =
     3
     5
     1
>> b = [3; 2; 3; 4]
b =
     3
     2
     3
     4
>> abs(a-b')./max(a,b')
ans =
         0    0.3333         0    0.2500
    0.4000    0.6000    0.4000    0.2000
    0.6667    0.5000    0.6667    0.7500
>> abs(bsxfun(@minus,a,b'))./bsxfun(@max,a,b')
ans =
         0    0.3333         0    0.2500
    0.4000    0.6000    0.4000    0.2000
    0.6667    0.5000    0.6667    0.7500

Best Answer

Related Solutions

MATLAB: I did some changes in red,green,blue channel of the image .Now when is am using cat function it is giving me full white image.This is not the output i want

MATLAB: Bsxfun – @minus – how to divide by maximum

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