MATLAB: Deleting the row of a 3D matrix with a condition

deleting rowsMATLAB

I have a simple 3D matrix. Every time I do this operation on the (:,:,1) matirx it gives me an error saying "A null assignment can have only one non-colon index." I dont understand this. But in a simple 2D matrix it works. If I assign "NaN" instead of "[]" then the second row is assigned with NaN NaN values (in 3D). Can I not delete the row in a 3D matrix? Appreciate some insight to this.
A(:,:,1) = [1 2 ; 0 5 ; 7 8 ];
A(:,:,2) = [10 11 ; 1 14 ; 0 17 ];
A((A(:,1,1).*A(:,2,1))==0,:,1)=[]

Best Answer

Of course you cannot delete one row in a 3D array: The resulting array must have the same length for all subvectors. Removing a row from a 3D array is equivalent to removing one element from a matrix: The result would not be rectangular anymore, but matrices must have the same number of elements for all rows, and all columns, respectively.
A(:,:,1) = [1 2 ; 0 5 ; 7 8 ];
A(:,:,2) = [10 11 ; 1 14 ; 0 17 ];
B = A;
B(:, :, 1) = []  % Working
A(1, :, 1) = []  % Error: output cannot be a valid array
Therefore I cannot guess, what you expect as output and cannot suggest a solution. Assigning NaN to a row works, because this does not change the number of elements.
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