Suppose I have a set of data (a 2×9 matrix):
data2 =
[ 1] [0.0095] [5670000] [936] 'Normal' [0] [0] [0] [ NaN] [ 2] [0.0095] [5670000] [936] 'Normal' [0] [0] [0] [ NaN] [ 3] [0.0095] [5670000] [936] 'Normal' [0] [0] [0] [ NaN] [ 4] [0.0095] [5670000] [936] 'Normal' [0] [0] [0] 'some text' [ 5] [0.0095] [5670000] [936] 'Normal' [0] [0] [0] 'some text'
I want to be able to detect the NaN's and delete the first three columns.
Typically this is done through
data1(find(sum(isnan(data2),2)==0),:)but isnan is for input arguements of type 'cell'. What else can I try?
Best Answer