MATLAB: Curvature of mode shape curveture Can you please help me how to write this code? I have x=[…] y=[….] i=size(x) and need to calculate r[…]=y(i+1)+y(i-1)-y(i)/h^2 h = x(i)-x(i-1) Best Answer Already you have written what you want and it should be bit placed properly. Let y be your array.n = length(y) ; r = zeros(n-2,1) ; for i = 2:n-1 h = x(i)-x(i-1) ; r(i) = (y(i+1)+y(i-1)-y(i))/h^2end Related SolutionsMATLAB: Index exceeds the number of array elements (11) h = 0.01; % time stepdxdt = @(x,y) y;dydt = @(x,y) x-x^3;m = 100 ;x = zeros(m,1) ;y = zeros(m,1) ; x(1)=1;y(1)=1;for i=1:1:m-1 x(i+1) = x(i) + h*dxdt(x(i), y(i)); y(i+1) = y(i) + h*dydt(x(i), y(i));end% Data Matrices X X = [x y x.^2 x.*y x.^2.*y x.*y.^2 y.^2 y.^3 y.*x.^3 x.*y.^3 y.^3 x.^4 y.*x.^4 y.^4]; MATLAB: Curvature direction Is the circle actually part of an image, or do you have the coordinates of the circle? If you have the coordinates, it's just a matter of calculating the sign of the cross product. cp = cross( [x(2)-x(1), y(2)-y(1), 0], [x(3)-x(1), y(3)-y(1), 0]) direction = sign(cp); %+1 if counterclockwise, -1 if clockwise Related QuestionRadius of Curvature ArrayHow to loop itWon’t run euler methodFinding curvature of plotRadius of curvature calculation
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