MATLAB: Creating a matrix with [xb^2, xb, 1]

Question

I'm trying to create this matrix where we have A = [xb.^2, xb, 1]. It will be a 3×36 matrix where I have found 36 values for xb.^2 and xb, and will have 36 1s in the matrix as well. I'm trying to put it all together right now, and I'm not sure how.

Here's what I have so far:

 M = csvread('filename.csv',1,0);
 N = csvread('filename.csv',1,0);
 n = length(N(:,4));
 m = length(M(:,4));
 x = -1:1.8/36:0.8;
 for t = 1:36
    a = 0; b = 0; ymsum = 0; ynsum = 0;
    for i = 1:n
        if -N(i,4) < x(t+1) && -N(i,4) > x(t)
            ynsum = ynsum + N(i,5);
            a = a+1;
        end
    end
    for o = 1:m
        if -M(o,4) <= x(t+1) && -M(o,4) >= x(t)
            ymsum = ymsum + M(o,5);
            b = b+1;
        end
    end
    xb(t) = (x(t)+x(t+1))/2;
    ymb(t,1) = ymsum/a;
    ynb(t,1) = ynsum/b;
 end

The matrix is ideally supposed to look like:

    A = [xb(1).^2   xb(1)   1
         xb(2).^2   xb(2)   1
         xb(3).^2   xb(3)   1
            .         .     .
            .         .     .
            .         .     .
         xb(36).^2  xb(3)   1]

It's probably really simple, but I'm not seeing it. Thank you.

Answer 1

A = [xb(:).^2 xb(:) ones(numel(xb),1)];