MATLAB: Create y using x, without loop

MATLABvectorization

size x = 2,3
size y = 1,157
y(3:52,1) = 1; y(53:102) = 2;… I need this but in one line of code that doesn't involve a loop.
X is dynamically growing because it is pulling data from another array. In X, columns 1&2 represent the index of rows needed for Y; however, column 3 is data inputted to Y for each of those rows respectively. Columns 1&2 will always be ordered consecutively column 3 will not.
x =
[ 3 52 1
53 102 2
103 157 98]
y =
[0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 98 98 98…]

Best Answer

No loop method (assuming consecutiveness)
This solution assumes the indices defined in columns 1&2 are consecutive and without gaps. 
y = [zeros(1,x(1,1)-1), repelem(x(:,3),x(:,2)-x(:,1)+1,1)'];
No loop method (the silly method)
This method works even when indices are not consecutive and have gaps. 
x = [ 3   52	1
     53   102	2];
xc = mat2cell(x,ones(1,size(x,1)),size(x,2)); 
yc = cellfun(@(x)ones(1,x(2)-x(1)+1).*x(3), xc, 'UniformOutput',false);
xIdx = cellfun(@(x)x(1):x(2), xc,'UniformOutput', false);
y = zeros(1,max(max(x(:,[1,2]))));
y(cell2mat(xIdx')) = cell2mat(yc');
Loop method (the better & fastest method)
This method works even when indices are not consecutive and have gaps. 
x = [ 3   52	1
     53   102	2];
y = zeros(1,max(max(x(:,[1,2]))));
for i = 1:size(x,1)
    y(x(i,1):x(i,2)) = x(i,3);
end
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