MATLAB: Create array address using for loop

arrayloop

I need to use for loop for creating address in structure example

For i=1:1:5000
[A(i),B(i),C(i)]=imread('fff',(i-1));
end;

I know this program is wrong.

I want files to be created as A1=some numbers,B1=some numbers….

A2=some numbers,B2=some numbers….

A3=some numbers,B3=some numbers….

A5000=some numbers,B5000=some numbers….

to be saved in workspace.

Thank you in advance

Best Answer

Just use cell arrays:

N = 5000;
A = cell(1,N);
B = cell(1,N);
C = cell(1,N);
for k = 1:N
    [A{k},B{k},C{k}] = imread('fff',k-1);
end

https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html

Related Solutions

MATLAB: Concatenate arrays within a loop,

Easy, given any number of arrays in a cell array C. You could use a loop like this, although it is inefficient because the output array is not preallocated:

C = {[1,2],[3,4],...} % cell array of arrays.
A = C{1};
for k = 2:numel(C)
    A = [A;C{k}];
end

Simpler and more efficient would be to concatenate them all at once, without a loop, e.g.:

A = vertcat(C{:})

Whatever you do, do NOT try to access variable names dynamically in a loop! Read this to know why:

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

Using an array (e.g. a cell array) and indexing is much simpler, neater, much more efficient, less buggy, and easier to debug.

MATLAB: How to find the start and end points of overlapping intervals in one array

a = [ 1.5000 95.5000; 82.5000 150.5000; 141.5000 197.5000; 191.5000 357.5000; 400.5000 438.5000; 415.5000 481.5000; 519.5000 667.5000];
b =  reshape(a',1,[]);
ii = strfind(sign(diff(b)),[-1 1]);
out = b;
out([ii,ii+1]) = [];

add

b =  reshape(a',1,[]);
x = all(tril(bsxfun(@lt,b(:),b(:)'))==0,2);
i0 = strfind(x(:)',[1 0]);
x(i0) = false;
out = b(x);

add2

a = [ 4.5000   58.5000
    4.5000   58.5000
   65.5000  118.5000
   65.5000  118.5000
  140.5000  277.5000
  140.5000  277.5000
  206.5000  223.5000
  206.5000  223.5000
  284.5000  295.5000
  284.5000  295.5000
  360.5000  422.5000
  360.5000  422.5000
  449.5000  454.5000
  449.5000  454.5000
  449.5000  532.5000
  449.5000  532.5000
  532.5000  574.5000
  532.5000  574.5000]
a1 = unique(a,'rows');
out = a1(1,:);
for jj = 2:size(a1,1)
    if out(end,2) > a1(jj,1) && a1(jj,2) > out(end,2)
        out(end,:) = [out(end,1) a1(jj,2)];
    elseif out(end,2) <= a1(jj,1)
        out(end + 1,:) = a1(jj,:);
    end
end

a1 = unique(a,'rows');
for jj = 2:size(a1,1)
    if a1(jj-1,2) > a1(jj,1) && a1(jj,2) > a1(jj-1,2)
        a1(jj,1) = 0 ;
        a1(jj-1,2) = 0;
    elseif a1(jj-1,2) >= a1(jj,2)
        a1(jj,:) = 0;
    end
end
out = a1';
out = reshape(out(out>0),2,[])';

Best Answer

Related Solutions

MATLAB: Concatenate arrays within a loop,

MATLAB: How to find the start and end points of overlapping intervals in one array

Related Question