That can be done in 3 lines of code tops. However, giving you the solution for your assignment straight away does not seem fair.
Finding the nmax satisfying your threshold should not be hard analytically.
After that, you can use the builtin function sum to calculate the sum of the elements of a vector containing the terms 1/n^2 up to the threshold you calculated.
Take a look at the elementwise operations ./ and .^2.
Total, three lines of code, if you build the vector in a separate instruction
1) calculate the threshold
2) build the vector
3) sum the vector
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