having a function
fa=@(x) x^5-0.4475*x.^4-3.1*x.^3 + 3.085*x.^2-0:962*x+ 0:0943
how to calculate
dfa=@(x) diff(fa)
so that it is still a function and i can calculate,for example:
dfa(5)
differential equationsfunctionmatlab function
fa=@(x) x^5-0.4475*x.^4-3.1*x.^3 + 3.085*x.^2-0:962*x+ 0:0943
dfa=@(x) diff(fa)
dfa(5)
Best Answer