MATLAB: Could anyone help to covert the equation into matlab code

codeequationequation into code

How to convert this into code?

Best Answer

Not sure what arrays p and g should be.

B=sum(log(1+(p(2:n).*g(2:n))./(1+arrayfun(@(x)sum(x*g(3:n)),p(2:n))))/log(2));

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MATLAB: How do is code this last summation? I was able to do the first one but have no clue how to finish it

Maybe a little bit clearer version:

y= 7.5, n=16, L=16 result: 118.22

y= 4, n=1, L=3 result: 46.31

function main 
    % input values
    y = 4;
    L = 3;
    z = 17;
    n = 1;
    av = 0;
    for i = 1:z-2
        x = L/(z-1)*i;
        av = av + s(x,y,n,L);       
    end
    x = L/(2*z-2)*i;
    av = av + s(x,y,n,L) + s(L-x,y,n,L);
    av = av/z;
    display('Average Brightness: '), av
end
function result = s(x,y,n,L)
    % equations
    E = 808.01/y^2.008;
    a = L/(2*n);
    c = @(i) atand( abs(x-a*[2*i-1])/y );
    coeff = [
        -0.0000000667
         0.0000157209
        -0.0010081511
         0.0020817855
         0.9991821678];
    S = 0;
    for i = 1:n
        for j = 1:5
            S = S + coeff(j)*c(i)^(5-j);
        end
    end
    
    result = E*S;
end

MATLAB: I tried to call a function but it failed

It is fundamental to the idea of functions in all programming languages that the variable names inside the function are internal to the function, that assigning to a variable inside the function does not affect the calling environment unless special arrangements are made.

Your assigning to the R_tow variable that belongs to the function rate() does not affect any variable outside of rate().

In order to get what you want, at the place you have

rate(tow0);

You need instead

R_tow = rate(tow0);

This R_tow is not the same variable as the one inside of rate(). Assignment of results is positional not according to name.

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Related Solutions

MATLAB: How do is code this last summation? I was able to do the first one but have no clue how to finish it

MATLAB: I tried to call a function but it failed

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