MATLAB: Could anyone help me to overcome the error.

too many output arguments error

code:
C = partitions(3)
home
partdisp(C)
Y = cell2num(partdisp(C))
If i run the code i am getting error stating Error using partdisp
Too many output arguments.
Error in line 17
 Y = cell2num(partdisp(C)).

Could anyone help me on this

Best Answer

partdisp is part of a file exchange contribution. It is defined as not returning any variables and as displaying the output to the command window. You can modify the code if that is not what you need.

Related Solutions

MATLAB: Pre allocating triple loops

n = numel(L);
c = cell(n,n,45);
for ii = 1:n
    for jj = 1:n
        for kk = 1:45        
            c{ii,jj,kk} = cross(L1(ii,:),a{jj}(kk,:));
        end
    end
 end

MATLAB: Could anyone help me how to split the {1×3 cell}

function [] = partdisp(A,K)
if nargin>2
    error('A maximum of two input argument is allowed.')
end
if ~iscell(A)
    error('This function is only useful on the output from PARTITIONS.')
end
L = length(A);
fprintf('\n')
if iscell(A{1}{1})
        if ischar(A{1}{1}{1})
            f = '%s ';
        else
            f = '%g ';
        end
        for ii = 1:length(A)
            for jj = 1:length(A{ii})
                for kk = 1:length(A{ii}{jj})
                    fprintf(f,A{ii}{jj}{kk})
                end
                fprintf('\b ')
            end
            fprintf('\n')
        end
    else
        if ischar(A{1}{1})
            f = '%s ';
        else
            f = '%g ';
        end
        for ii = 1:length(A)
            for jj = 1:length(A{ii})
                fprintf(f,A{ii}{jj})
                fprintf('\b ')
            end
            fprintf('\n')
        end
    end
fprintf('\n')

Best Answer

Related Solutions

MATLAB: Pre allocating triple loops

MATLAB: Could anyone help me how to split the {1×3 cell}

Related Question