MATLAB: Convert Unix Time in Date Time Format with Milliseconds

datedate timemillisecondstime stampunix_time

Hello,
i want to convert Unix Time Stamp like this 1545390864126080000 (1.545^18) in a Format like this "Friday, 21. December 2018 11:14:24.126".
I use:
date_time = datestr(unix_time_pose./86400 + datenum(1970,1,1));
unix_time_pose vector is Unix_Time/10^9 and i get something like this '21-Dec-2018 12:04:58'. It is the right date without milliseconds.
Can anyone help me how to get milliseconds,too?

Best Answer

What you have is 1ns ticks since 1970. That's sort of Posix time, but at a different resolution. If that's really what you have, you are gonna need to store the raw numbers as a uint64 array, double will not give you enough precision. So
>> t = uint64(1545390864126080000)
t =
  uint64
   1545390864126080000
>> d = datetime(t,'ConvertFrom','epochtime','TicksPerSecond',1e9,'Format','dd-MMM-yyyy HH:mm:ss.SSSSSSSSS')
d = 
  datetime
   21-Dec-2018 11:14:24.126080000
If you don't care about anything smaller than ms, then you can use double.
>> t = 1545390864126
t =
             1545390864126
>> d = datetime(t,'ConvertFrom','epochtime','TicksPerSecond',1e3,'Format','dd-MMM-yyyy HH:mm:ss.SSS')
d = 
  datetime
   21-Dec-2018 11:14:24.126
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