MATLAB: Convert to MATLAB Code

convertMATLABmatlab function

Best Answer

Hi,

Following code illustrates the implementation of the above equation:

x=[2 3];      %x vector
f=function_5(x);
function f= function_5(x)
a=ones(2,25); % a(i,j)
sum1=0;
sum=0;
for j=1:25
    for i=1:2
        sum1= sum1 + (x(i) - a(i,j))^6;
    end
        sum = sum + 1/(j+sum1);
        suom1=0;
end
f=0.002+sum;
end

Hope it helps!!

Related Solutions

MATLAB: Finding Zero of Sum of Functions by Iteration

I think the solution is to write a function:

 function [ sum ] = func(j,g,t,X)
    sum = 0;
    for i = 1:2*j+1
        f = exp(-exp(X(i,j)+g)*(t(j+1)-t(j)));
        sum = sum + f;
    end
 end

Then loop your solver

 for j=1:n
  fun = @(g)func(j,g,t,X);
  fzero(fun,0)
end

You'll have to debug the function inside( f = stuff ) (since I don't know what it's supposed to do) so that it returns what you want, but this should solve your problem.

I can get this to solve, but I'm not sure if your f function does what you want it to do.

MATLAB: Defining matrices to solve Ax=b using a(i,j)=-1+2max(i,j) and b(j)=sum(j to n) a(i,j)

Replace your code with:

summ=0;  
for j=1:n
  summ=sum(A,2)
end

so there is no confusion between the variable summ and the function sum.

Best Answer

Related Solutions

MATLAB: Finding Zero of Sum of Functions by Iteration

MATLAB: Defining matrices to solve Ax=b using a(i,j)=-1+2max(i,j) and b(j)=sum(j to n) a(i,j)

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