MATLAB: Conversion of [0,1] to Binary

Hi, I want to convert decimals between 0 and 1 into binary form which can be represented exactly up to 11 binary digits say, so 1/2^11, 2/2^11, 3/2^11……to 2^11-1/2^11 only, is there a good code or build in function for this?

Also, is there a function which can return the no of 1's or 0's in the binary form of a particular value above?

Thanks

Joe

Best Answer

B = dec2bin( round(X * 2^11), 11 ) - '0';
nnz(B)
sum(B)
length(B) - nnz(B)

Related Solutions

MATLAB: How to convert a binary fraction to decimal

'11001' means: 1*2^0 + 0*2^1 + 0*2^2 + 1*2^3 + 1*2^4 or:

[1,1,0,0,1] * 2 .^ (4:-1:0).'

(this is what happens inside bin2dec - examine its source code.)

'0.10011' means: 1*2^-1 + 0*2^-2 + 0*2^-3 + 1*2^-4 + 1*2^-5, or:

[1,0,0,1,1] * 2 .^ (-1:-1:-5).'

So all you have to do is to split the part before and after the decimal dot and to convert the character to numbers. Both is easy in Matlab:

S = strsplit('11001.10011', '.');
intV      = S{1} - '0';
fracV     = S{2} - '0';
intValue  = intV  * (2 .^ (numel(intV)-1:-1:0).')
fracValue = fracV * (2 .^ -(1:numel(fracV)).')
% or:
            sum(fracV ./ (2 .^ (1:numel(fracV))))
% [EDITED] Typo fixed: ^  this was \ before

Best Answer

Related Solutions

MATLAB: How to convert a binary fraction to decimal

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