MATLAB: Complex function inverse plot inverse Hello, i have a plot a function y=1/(ln(x)-0.1) how can i plot X as a function of Y ,when y=[5:0.01:6] Thanks. Best Answer On solving it manually....we have:y = 1/(log(x)-0.1) ;x = exp(1/y+0.1) ; To plot: y=[5:0.01:6] ;x = exp(1./y+0.1) ; plot(x,y) Related SolutionsMATLAB: How to animate two functions at the same time m = 100 ; x1=linspace(0,exp(1)-0.01,m); x2=linspace(exp(1)+0.01,10,m);y1=(log(x1)/log(exp(1))-2)./(log(x1)/log(exp(1))-1); %first functiony2=(log(x2)/log(exp(1))-2)./(log(x2)/log(exp(1))-1); %second functionX = [x1' x2'] ; Y = [y1' y2'] ; for i = 1:m plot(X(1:i,:),Y(1:i,:)) ; drawnowend MATLAB: Plot the exp function syms y(t)eq=diff(y,2)+13*diff(y)+40*y==4;Dy=diff(y);Y(t)=dsolve(eq,[y(0)==0 Dy(0)==0])t=0:0.001:0.9;plot(t,Y(t)) Related QuestionHow to plot lnxHow to plot a sym function with constant function such as x=2(vertical line) & y=3(horizontal line)How can i plot this equation
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