MATLAB: Comparision of a matrix to a value

comparisionMATLAB

I want to compare values of a matrix of 4 by 3 dimension

for example

a=[7 8 8 ;5 3 2 ;1 2 3;7 6 5]

to a 1by1 matrix

b=[ 5]

if the values are greater than 5 the codes give me a 1 and 0 if not in a matrix of same dimension as a.What should i do??

Best Answer

a=[7 8 8 ;5 3 2 ;1 2 3;7 6 5];
b=5;
result=a>b

Related Solutions

MATLAB: Managing maximum and minimum values in the elements of an matriz.

This should work. The idea is to first find out the base number, adjust the offset if needed, and add the base back.

A = [2.1  3.0  4.4  5.5   6.1
    2.3   3.2   4.2   5.4   6.3
    2.1   3.1   4.1   5.2   6.2
    2.2   3.1   4.1   5.1   6.6
    2.0   3.3   4.3   5.3   6.4];
lim=0.1;
base=repmat(1+(1:size(A,2)),size(A,1),1);
dist_to_base=A-base;
dist_to_base(dist_to_base<=   lim   )=lim;
dist_to_base(dist_to_base>= (1-lim) )=1-lim;
B=base+dist_to_base;

MATLAB: How to find the mean values betwwen 3 matrix

This works:

A= [1,2,8; 5,6,7;7,5,8];
B=[0.2,5,1; 0.55,8,4;55,7,9];
C=[1,5,7; 2,6,8;0.6,7,1];
Cat = cat(3, A, B, C);
D = min(Cat, [], 3)
D =
            0.2            2            1
           0.55            6            4
            0.6            5            1

Your desired result is not the average or mean values, but the minimum or min values.

If you actually want the average or mean values, change the ‘D’ assignment to:

D = mean(Cat, 3)

I separated out the concatenated matrices, ‘Cat’ assignment so you could see how the code works. You can of course combine them ionto one statement.

Best Answer

Related Solutions

MATLAB: Managing maximum and minimum values ​​in the elements of an matriz.

MATLAB: How to find the mean values betwwen 3 matrix

Related Question

MATLAB: Managing maximum and minimum values in the elements of an matriz.