MATLAB: Code Explaination (For Loop)

for loop indexing

 function [y]=f6(x)
 global data 
 x=abs(x); 
n=length(data(:,1));
for i=1:n-1
    if x(i)>1;
        x(i)=1;
    else
    end
    P(i)=data(i+1,4)+x(i)*(data(i+1,5)-data(i+1,4));
end

Can anyone explain the for loop please?

My data is a 3×5 matrix & i'll use it for genetic algorithm.

Best Answer

The code is doing linear interpolation between column 4 and column 5, using abs(x) as the portion of the way between the columns.

Related Solutions

MATLAB: Concatenate matrix numbers linspace

try this

 x = [0.25 1 1.5 2 2.4 2.6]
 x=unique(sort([x x(1:length(x)-1)+diff(x)/2]) )

if you want put 2^n-1 samples between each value use this function

 function y=linspace_n(x,n)
 for k=1:n
 x=unique(sort([x x(1:length(x)-1)+diff(x)/2]) )
 end
 y=x

MATLAB: Interp1 or its alternatives, working for matrices without loop

So you're going over column by column, creating columns of 60 out of columns of 30. Assuming your xi are just exactly between the elements and exactly on the elements, you can just assume the "in between" interpolations are just the average of the two elements on either side. Thus you can just use a sliding mean filter. Use conv2(y(:,i), [.5; .5]) to give you the "in between" values, then just interleave it with the existing values. Exercise for the reader: interleave the convolution output with the original matrix. (It's like 3 lines of code or so.) Let me know if you can't figure it out and need help.

If your xi are spaced out at non-periodic oddball locations then you can't use conv2.

Best Answer

Related Solutions

MATLAB: Concatenate matrix numbers linspace

MATLAB: Interp1 or its alternatives, working for matrices without loop

Related Question