It is not clear why you need to structure at all, as the output is simply a cell array with some numeric scalars in it (Octave code below)
>> {[struct('field',1) struct('field',2)].field}
ans =
{
[1,1] = 1
[1,2] = 2
}
>> {struct('field',{1,2}).field}
ans =
{
[1,1] = 1
[1,2] = 2
}
>> {1,2}
ans =
{
[1,1] = 1
[1,2] = 2
}
Best Answer