MATLAB: Can using cell arrays produce unexpected matrix dimension errors

cell arraysMATLAB

I'm attempting to write default data values to a text file using the following code;
Default_Cam_Data = {
'Cam ID:' 1 ;
'pad 6:' -1 ;
'SW ID:' 1 ;
'Position:' 0.0000000, 0.0000000, 0.0000000 ;
'Range:' 0.0 ;
'Cam Status:' -1 ;
'Tolerance Count:' 0 };
[nrows,ncols]= size(Default_Cam_Data);
filename = 'camera_data.txt';
fid = fopen(filename, 'w');
Total_Cams_Reporting = 3;
for m = 1:Total_Cams_Reporting
fprintf(fid, 'Observing Cameras Info (%d of %d)\n', m, Total_Cams_Reporting);
for row=1:nrows
fprintf(fid, '%s %d\n', Default_Cam_Data{row,:});
end
end
fclose(fid);
When I open the text file, I expect the data to be written like this;
Observing Cameras Info (1 of 3)
Cam ID: 1
pad 6: -1
SW ID: 1
Position: 0.0000000, 0.0000000, 0.0000000
Range: 0
Cam Status: -1
Tolerance Count: 0
Observing Cameras Info (2 of 3)
Cam ID: 1
pad 6: -1
SW ID: 1
Position: 0.0000000, 0.0000000, 0.0000000
Range: 0
Cam Status: -1
Tolerance Count: 0
Observing Cameras Info (3 of 3)
Cam ID: 1
pad 6: -1
SW ID: 1
Position: 0.0000000, 0.0000000, 0.0000000
Range: 0
Cam Status: -1
Tolerance Count: 0
However, I keep getting the following error:
Warning: File: Cam.m Line: 2 Column: 20
The expression on this line will generate an error when executed. The error will be: Error using vertcat Dimensions of matrices being concatenated are not consistent.
Error using Cam (line 1) Error using vertcat Dimensions of matrices being concatenated are not consistent.
I suspect the problem has something to do with the 3 default values for position since I can delete the last 2 occurences of 0.0000000, and I get this result: Position: 0
This is the first time I've seen this. Any ideas on what could be the source of this error?

Best Answer

Hey Brad,
vertcat() is what is called when you use a ";" to vertically concatenate an array, e.g.:
x = [1; 3]
is equivalent to
x = vertcat(1,3)
What's happening with your file above is you have a bunch of 1x2 rows and then you try to concatenate them vertically with a 1x4 row.
'Cam ID:' 1 ;
'pad 6:' -1 ;
'SW ID:' 1 ;
'Position:' 0.0000000, 0.0000000, 0.0000000 ; % This guy has four elements
You'll need to either make the whole cell array an nx4 or figure out how to reduce those three 0.00000s to one, possible using a nested cell {0.00 0.00 0.00}