MATLAB: Can somebody tell me why, when I call a function using an input, the input is disregarded

matrix

I have a function,
function cubefinal = sensingmatrix3d(time)
and I call it like this if I want time=3:
cubefinal = sensingmatrix3d(3);
but it is not working (the body of the function is correct) because when I displayed 'time', answers seemed totally random:
>> test3dmatrix
time =
       6
>> test3dmatrix
time =
       6
>> test3dmatrix
time =
       7
>> test3dmatrix
time =
       7
>> test3dmatrix
time =
       4
>> test3dmatrix
time =
       5
could somebody please tell me why time is random? and how to fix it? thank you.
Edit: sorry — here is my code
function cubefinal = sensingmatrix3d(time)
exposure=zeros(60,96,10);
if time==3
   for j=1:size(exposure,1);
    for jj=1:size(exposure,2);
        randnum=randi([1 8]);
        exposure(j,jj,randnum:randnum+2)=1;
        %if rand < 0.003
        %    checkRow=reshape(exposure(j,jj,:), [1 10])
        %end
    end
   end
elseif time == 4 
    for j=1:size(exposure,1);
    for jj=1:size(exposure,2);
        randnum=randi([1 7]);
        exposure(j,jj,randnum:randnum+3)=1;
    end
    end
elseif time == 5 
    for j=1: size(exposure,1);
    for jj=1:size(exposure,2);
        randnum=randi([1 6]);
        exposure(j,jj,randnum:randnum+4)=1;
    end
    end
elseif time == 6 
    for j=1:size(exposure,1);
    for jj=1:size(exposure,2);
        randnum=randi([1 5]);
        exposure(j,jj,randnum:randnum+5)=1;
    end
    end
elseif time == 7 
    for j=1:size(exposure,1);
    for jj=1:size(exposure,2);
        randnum=randi([1 4]);
        exposure(j,jj,randnum:randnum+6)=1;
    end
    end
end
   cubefinal=exposure;
disp(time)
end

Best Answer

You show code for function sensingmatrix3d, but your example is calling test3dmatrix. How are the two related? Look at how test3dmatrix is calling your function.
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