MATLAB: Can anyone please tell, how can I normalize the magnitude between 0 to 1?? Currently it is varying upto (2*10^6). I want it to vary between 0-1.

communicationplotting histogram for magnitude of rayleigh fading channel

N = 10000000; stepsize = .05;
a = 0:stepsize:4;
% Rayleigh model
% Amplitude plot
Rayleigh_ch = (randn(1,N)+1i*randn(1,N))/sqrt(2);
b = abs(Rayleigh_ch);
%c = b/(stepsize*sum(b));
norma = b - min(b(:))
normA = norma ./ max(norma(:)) % 
fig = figure;
hist(normA,a);

Best Answer

The way you have "normalized", the maximum value of normA is 1.

I suspect that what you want is for the sum to be 1, rather than the maximum value. If that is correct, then do

normA = norma ./ sum(norma(:)); %

instead of

normA = norma ./ max(norma(:)); %

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MATLAB: Ode solver varying parameters

You do not assign multiple values to p7. Instead, each time that p7 needs to change values in a discontinuous way, you need to terminate the ode45, and then restart it from where you left off except with the new p7 value.

If the p7 changes happen at known times, then the way to do this is to call ode45 with tspan reflecting the interval in which p7 is to remain constant. For example,

p7times = [0, 1, 2.5, 5, 5.2, 10];
p7vals = [pi/9, 0.3, exp(-1), sqrt(2), -3];  %one fewer
num_interval = length(p7vals);
x0 = [0 0 0];
t = cell(num_interval,1);
x = cell(num_interval, 1);
for idx = 1 : num_interval
    p7 = p7vals(idx);
    [t{idx},x{idx}] = ode45(@(t,x) try_eqns(t, x, p7), p7times(idx:idx+1), x0);
    x0 = x{idx}(end,:);
end

If discontinuous changes to your p7 depend upon the results of the ode, then you should instead use ode event functions to detect the situation and terminate the integration and then resume with the new p7. There is a useful example of this: see ballode

Best Answer

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