I have a function of two variables 'x1' and 'x2' and I want to maximise that function
F(x1,x2) = ((1 + x1/x2) * 725.2) – 398
subject to: x1 <= 5; x2 <= 120; x1 >= 1; x2 >= 40
Please help I shall be thankful
MATLAB: Can anyone help me in optimizing (maximizing) the function of two variables
nonlinearoptimization
Related Solutions
It's a typo in the 4th line, remove the > and use
x2 = x1.*2Note that if x1 is not <= 0, it must be > 0 , so you there is no need to test for >=0 in the elseif clause. So you can simply use else:
if x1 <= 0 x2 = x1./2else x2 = x1.*2end%{
x1+x2+x3+x4+x5 =1000;x1^2-4x2+5x3^3+x4^4-3.5x5^2 = 300%}
Notice that x2 is the only variable that appears linearly in the second equation. So rewrite the first equation as
%{x2 = 1000 - x1 - x3 - x4 - x5%}Now substitute that into the second equation
%{x1^2-4*(1000 - x1 - x3 - x4 - x5)+5x3^3+x4^4-3.5x5^2 = 300%}This is a quadratic in x1 (or x5), so solve it for x1
syms x1 x2 x3 x4 x5eqn = x1^2-4*(1000 - x1 - x3 - x4 - x5)+5*x3^3+x4^4-3.5*x5^2 == 300
X1 = solve(eqn, x1)
Now you run two different PSO runs, one substituting 1000 - x1 - x3 - x4 - x5 for x2 and the first of those X1 values for x1; the other run substituting 1000 - x1 - x3 - x4 - x5 for x2 and the second of those X1 values for x1. These runs will not require equality or inequality constraints (unless there are more constraints you did not tell us about.)
The runs you would do would be over 3 variables only, x3, x4, x5, with you having substituted for x1 and x2 in your objective function.
Best Answer