MATLAB: Calculate vowels consonants spaces numbers in a sentence

for loopif statementMATLAB

clc

close all

cons=0;

vowels=0;

spaces=0;

num=0;

sp=0;

strg=input('Given string is : ','s');

l=strlength(strg);

for i=1:l

if strg(i)=='a' || strg(i)=='e' || strg(i)=='i' || strg(i)=='o' || strg(i)=='u' strg(i)=='A' || strg(i)=='E' || strg(i)=='I' || strg(i)=='O' || strg(i)=='U'

vowels=vowels+1;

elseif (strg(i)>= 'a' && strg(i)<='z') || (strg(i)>= 'A' && strg(i)<='Z')

cons=cons+1;

elseif strg(i)==' '

spaces=spaces+1;

elseif strg(i)>=0 && strg(i)<=9

num=num+1;

else

sp=sp+1;

end

fprintf('Number of vowels=%d',vowels);

fprintf('Number of consonants=%d',cons);

fprintf('Number of spaces=%d',spaces);

fprintf('Number of numbers=%d',num);

This is my code and I am getting an error at line 11 . Can anyone please help me out and check if there are any other errors?

Best Answer

Hi Aagam

It is my understanding that you are trying to count the number of vowels, consonants, spaces, and numbers in a given string. However, you're getting the error.

This error is occurring because of line 11. There should be an OR (||) operator in-between " strg(i)=='u' " and " strg(i)=='A' ".

Please refer to the https://in.mathworks.com/help/matlab/logical-operations.html (logical operator) documentation for more information on how to use logical operators.

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MATLAB: How to discard all punctuation from a text file

Star Stride is right but perhaps Fateme wants to keep the spaces, because space is not punctuation spaces will help reading the resulting string. The initial string

str1 = 'Hello, I need 1 MATLAB code to discard all punctuation, and signs from 9 text files.'
Lstr1=length(str1)

the characters that have to remain are

str_space='\s'
str_caps='[A-Z]'
str_ch='[a-z]'
str_nums='[0-9]'

their respective positions within str1 are

ind_space=regexp(str1,str_space)
ind_caps=regexp(str1,str_caps)
ind_chrs=regexp(str1,str_ch)
ind_nums=regexp(str1,str_nums)
mask=[ind_space ind_caps ind_chrs ind_nums]

now let's find the position of all punctuation characters

num_str2=1:1:Lstr1
num_str2(mask)=[]

now num_str2 contains the positions of punctuation characters to remove

str3=str1
str3(num_str2)=[]

str3 contains the resulting string without any other character than alphabetical characters and numbers.

str3 =
Hello I need 1 MATLAB code to discard all punctuation and signs from 9 text files

Hope it helps in your reading.

John

jgb2012@sky.com

MATLAB: How to make a function that decides whether a word starts with a vowel

function y=vowel(input)
if regexp(input,'\<[aeiou | AEIOU]')==1
   fprintf('This word starts with a vowel\n');
   y=true;
else
   fprintf('This word does not start with a vowel\n');
   y=false;
end
end

Best Answer

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MATLAB: How to discard all punctuation from a text file

MATLAB: How to make a function that decides whether a word starts with a vowel

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