MATLAB: Calculate velocity from position and time

differentiablehomeworkloops derivatives velocity

I have to write a program to calculate the velocity given position and time in two arrays.

Best Answer

pos = rand(100,1) ;
t = 1:100 ;
v = zeros(length(t)-1,1) ;
for i = 1:length(t)-1
    v(i) = (pos(i+1)-pos(i))/(t(i+1)-t(i)) ;
end

Related Solutions

MATLAB: Discretization of position and velocity

First, the condition

if 0 < x(1) < 2*pi

is not doing what it seem it does. The correct it

if 0 < x(1) && x(1) < 2*pi

Beside, why do you use the if block when you are using mod function which will automatically wrap all values in the interval [0,2*pi]. Check the following code

function s = discretize_state(x, par)
    % TODO: Discretize state. Note: s(1) should be
    % TODO: position, s(2) velocity.
    x(1) = mod(x(1), 2*pi);
    s(1) = round(x(1)/(2*pi)*(par.pos_states-1) + 1);
end

MATLAB: Indexing in a while loop

Your line

atot(i)=athrust(i)-ag; % total acceleration

does not define an equation. It is executed only once, with the current value of i, so atot becomes a scalar.

Then in your line

    v(i+1)=v(i)+((atot(i+1)+atot(i))/2)*dt;

on the first iteration you have the problem that atot(1+1) does not exist.

After your while loop,

    nofuel_pos = find(mfuel <= 0, 1);

and then you can index your arrays at nofuel_pos or nofuel_pos - 1 as appropriate.

Best Answer

Related Solutions

MATLAB: Discretization of position and velocity

MATLAB: Indexing in a while loop

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