MATLAB: Calculate the sum of the following geometric series when N = 1000 and r =1/2 I have searched here and in the “help” in Matlab, but i found nothing about the geometric series

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calculate the sum of the following geometric series when N = 1000 and r =1/2 I have searched here and in the "help" in Matlab, but i found nothing about the geometric series

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If your geometric series is a, a*r, a*r^2, ..., a*r^N, then its sum is:

s = a*(1-r^(N+1))/(1-r)

Related Solutions

MATLAB: How can i calculate the sum of the following geometric series N= 1000 and r =0.99

N=0:1000;
r = 0.99;
E = r.^N;
sum(E)

MATLAB: Sum of geometric series without loop

I'm not all that clear on why you are using n=nargin instead of just passing n into the function as the second input but maybe there is more to your function than just the series.

You can try using cumprod which returns the cumulative product of each element in the input array. For example,

 cumprod([1 2 3 4 5])

returns

 1     2     6    24   120

where each element (starting from second) is multiplied by the previous element. You can do something similar with r and n as follows

 % create a vector with n elements all identical to r
 v = r*ones(1,n);
 % calculate [r r^2 r^3….r^n]
 v = cumprod(v);
 % sum and add one
 geoSum = 1 + sum(v);

Try the above and see what happens!

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Related Solutions

MATLAB: How can i calculate the sum of the following geometric series N= 1000 and r =0.99

MATLAB: Sum of geometric series without loop

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