MATLAB: BITXOR OPERATION

bitxor problem

Hello I want to do the "bitxor" operation as shown in below code. But since bitxor takes only 2 arguments the following code gives ERROR. Please suggest a solution. Mail me at lokesh_jolly05@yahoo.co.in

L(3*(i-1)+1)=mod(bitxor(B1(3*(i-1)+1),uint64(mod((abs(X(i))-floor(abs(X(i))))*10^14,256)),256));

Best Answer

You have a bracket misplaced.

L(3*(i-1)+1)=mod(bitxor(B1(3*(i-1)+1),uint64(mod((abs(X(i))-floor(abs(X(i))))*10^14,256))),256);

Notice the ')' after 256 was moved to the end of the previous argument.

Related Solutions

MATLAB: How can i remove bits from a 8 bit pixel

No. In MATLAB all of the numeric datatypes , and char as well , are defined as being multiples of 8 bits long. It is not possible to remove 3 bits from any numeric datatype or from char.

The size of the datatype logical is not specified in MATLAB . On the other hand there is no documented mechanism for setting more than true or false for logical . There is evidence that logical is one byte and that it could be hacked to store additional values... but none of those hacks would permit removing 3 bits from a logical .

I recommend that instead of trying to remove bits from pixels that you extract bits instead . see bitget and bitset.

MATLAB: How to solve the problem

A1bits = reshape((dec2bin(typecast(A1, 'uint8'), 8) - '0').', 1, []);

This will be a row vector. Once you have done this up to A4 then you can do

[A1bits, A2bits, A3bits, A4bits]

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MATLAB: How can i remove bits from a 8 bit pixel

MATLAB: How to solve the problem

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