A=[1 3 -999 -999 -999 -999 4 9 8 -999 -999 -999]; Here I want to get averages of three elements by ignoring -999. But in the final answer, if there were cases with three -999 in a given sector, it needs to be replaced by NaN. For an example, final answer of the above should B=[2 NaN 7 NaN]
Thanks.
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