MATLAB: Array from matrix equations

arraymatrix

i have a matrix that solves 4 unknowns, instead of writing Va1 = ….(see below) four times is there a more efficient way to do this so i have a Va array.

%example.
Vo = [2 3 4 5]% Vo Vectors 
%

Vn = X\Y; % Solves at set of 4 unknowns
%
Va1 = (alpha*Vn(1))+((1-alpha)*Vo(1));
Va2 = (alpha*Vn(2))+((1-alpha)*Vo(2)); 
Va3 = (alpha*Vn(3))+((1-alpha)*Vo(3)); 
Va4 = (alpha*Vn(4))+((1-alpha)*Vo(4));

Best Answer

Vo = [2 3 4 5];
Vn - X/Y;
for i = 1:4
Va(i) = (alpha * Vn(i)) + ((1-alpha) * Vo(i));
end

Related Solutions

MATLAB: Loop until condition met

Vo = [30 15 13 10];% initial V old to calc Re and f.
MaxIter=1e10;
%






Cntr=0;
while true
Cntr=Cntr+1;
%
Re1 = (D(1).*Vo(1)) / nu;
%
Re2 = (D(2).*Vo(2)) / nu;
%
Re3 = (D(3).*Vo(3)) / nu; 
%
Re4 = (D(4).*Vo(4)) / nu;
%
A = [Matrix];
b = [Matrix];
Vn = A\b;% solves four unknowns at A\b
%
for i = 1:4
Va(i) = (alpha * Vn(i)) + ((1-alpha) * Vo(i));
end
if all(abs(Va-Vn(1:4))<1e-10) && all(abs(Va-Vo)<1e-10) 
   break;
end
if Cntr==MaxIter  % add this to avoid being stuck if there is no solution.
   break;
end  
Vo=Va;
end

MATLAB: Using end value in next iteration

Voo = [30 15 13 10]; 
Vo=Voo
while ~all([Va==Vo,Vo==Vn]) (needs to be approx equal to)
  Vo=Voo
  Re1 = (D(1).*Vo(1)) / nu;
  Re2 = (D(2).*Vo(2)) / nu;
  Re3 = (D(3).*Vo(3)) / nu;
  Re4 = (D(4).*Vo(4)) / nu;
  A = [Matrix];
  b = [Matrix];
  Vn = A\b;% solves four unknowns at A\b % (1 col, 4 rows)
  for i = 1:4
      Va(i) = (alpha * Vn(i)) + ((1-alpha) * Vo(i)); %(1 col, 4 rows)
      Vo(i) = Va(i); %Used as Vo for each in next iteration. (1 col, 4 rows)
  end
end

Best Answer

Related Solutions

MATLAB: Loop until condition met

MATLAB: Using end value in next iteration

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