Hi guys
I want the value of area_under_curve to be exactly 30000 from 8.5 to 17
Is this way true to use integral?
Using matlab R2019b
clc;clear;close all;gauss = @(x,mu,sig,amp,vo)amp*exp(-(((x-mu).^2)/(2*sig.^2)))+vo;x = linspace(8.5,17,1000000);mu = 12;sig = 1.19895;amp = 10000;vo = 0; gauss = gauss(x,mu,sig,amp,vo);plot(x, gauss/1000, 'g-', 'LineWidth',.1)gauss = @(x)amp*exp(-(((x-mu).^2)/(2*sig.^2)))+vo;arear_under_crve = integral(gauss,8.5,17);
Best Answer