MATLAB: Adding elements to an array

arrays vectors loops for while adding

say I have an array

x=[0,0,2,3,4]

and a code

for n=1
    if (10^n)*p<q
        n=n+1;
    elseif (10^n)*p>q
        break
    end
end

is there a way to add an extra 0 to the start of x if my n value goes up. for example. If n is one x=[0,0,2,3,4] and if n is 2 x=[0,0,0,2,3,4] and if n=3 x=[0,0,0,0,2,3,4] and so on. Thanks for the help.

Best Answer

new_x = [zeros(1,n-1),x]

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MATLAB: How to return to a back step by checking back steps . problem in 4 and 5 step

After running the code upto here:

x=0.3;
x=0.3;
p=0.343;
for n=2:65536;
if x(n-1)>=0 & x(n-1)<=p
 x(n)=x(n-1)/p;
else
 x(n)=(1-x(n-1))/(1-p);
end 
end

You get x as an 1x65536 matrix. Then you have to calculate K like this:

for ii=1:numel(x)
K(ii)= mod(floor((x(ii)*10^2-floor(x(ii)*10^2))*10^3),256);
end

Then you have to check for each element of K w.r.t to the condition like this:

for ii=1:numel(K) % I assume L is total number of elements in K
if K(ii)<3
    K(ii)=K(ii)+3;
end 
end

I am not sure but is this what you are looking for? Where is the problem?

MATLAB: How can I play an audio, and in the middle of it, play a voice. but when the voice is played, the audio sounds 50% more slowly

vstart_at = 5000;
vlength = size(Voice,1);
slow_len = ceil(vlength/2);
p1 = x(1:vstart_at-1,:);
p2a = kron(x(vstart_at:vstart_at+slow_len,:), ones(2,1));
p2b = Voice;
if vlength ~= 2*slow_len
    p2b(end+1,:) = 0;
end
p3 = x(vstart_at+slow_len+1:end,:);
new_x = [p1;
         p2a + p2b;
         p3];

Best Answer

Related Solutions

MATLAB: How to return to a back step by checking back steps . problem in 4 and 5 step

MATLAB: How can I play an audio, and in the middle of it, play a voice. but when the voice is played, the audio sounds 50% more slowly

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