MATLAB: Add zero elemant inside cell

add zero elemant inside cell

A={[95],[112],[98],[84],[69],[121],[108]};
B={[1,2,4],[4,3],[6,9,98],[3,7,88],[2,9,1],[55,7],[1,4],[0],[0]};
if size(A,2)<size(B,2)
    % add zero at the end of A 
end

I want that size of A and B should be the same

result should be

A={[95],[112],[98],[84],[69],[121],[108],[0],[0]};

Best Answer

Simple indexing does exactly what you need:

>> A={[95],[112],[98],[84],[69],[121],[108]};
>> B={[1,2,4],[4,3],[6,9,98],[3,7,88],[2,9,1],[55,7],[1,4],[0],[0]};
>> A(end+1:numel(B)) = {[0]};
>> B(end+1:numel(A)) = {[0]};

Related Solutions

MATLAB: Add a value to an element in a matrix

Cause is a specific problem where I need to add that values of S just in these columns of A

Then, this should work:

A(S(1, :) ~= 0, 6) = nonzeros(S(1, :));
A(S(2, :) ~= 0, 2) = nonzeros(S(2, :));

Of course, if there were more rows in S a completely different approach would be better, but for just 2 rows this will do.

MATLAB: How to display averages in new array

OK, I changed it from a cell array to a double array like you wanted:

B=[100.0000  100.0000  100.0000  100.0000  100.0000  100.0000  100.0000  100.0000  100.0000  100.0000  100.0000  100.0000  100.0000  100.0000  100.0000  100.000;
  90.0000   90.0000   90.0000   90.0000  110.0000   90.0000   90.0000   90.0000  110.0000  110.0000  110.0000  110.0000  110.0000  110.0000  110.0000  110.000;
  81.0000   81.0000   81.0000   99.0000   99.0000   81.0000   99.0000   99.0000   99.0000   99.0000  121.0000  121.0000  121.0000  121.0000  121.0000  121.000;
  72.9000   72.9000   89.1000   89.1000   89.1000   89.1000   89.1000  108.9000   89.1000  108.9000  108.9000  108.9000  133.1000  133.1000  108.9000  133.100;
  65.6100   80.1900   80.1900   80.1900   80.1900   98.0100   98.0100   98.0100   98.0100   98.0100   98.0100  119.7900  119.7900  119.7900  119.7900  146.410]
% Extract the last row.
lastRow = B(end, :)
[rows, columns] = size(B)
% Get unique prices in the last row, for example [65.61, 80.19, 98.01]
pricesToSearchFor = unique(lastRow)
for k = 1 : length(pricesToSearchFor)
  thisPrice = pricesToSearchFor(k);
  fprintf('Searching all columns for price $%.2f.\n', thisPrice);
  % Search every column for this unique price.
  columnCounter = 1;
  for column = 1 : columns
    thisColumn = B(:, column);
    % Find out if this price occurs EXACTLY in the column
    lastIndexInColumn = find(thisColumn == thisPrice, 1, 'last');
    if ~isempty(lastIndexInColumn)
      fprintf('Found %.2f at row %d of column %d of B.\n', ...
        thisPrice, lastIndexInColumn, column);
      % If we found the price in this column, add it to a new column of A
      A(k, columnCounter) = mean(thisColumn(1:lastIndexInColumn));
      % Increment the column in A
      columnCounter = columnCounter + 1;
    end
  end
end
A

What it shows is:

A =
       81.902            0            0            0            0            0
       84.818       88.058       91.658       95.658            0            0
       91.622       95.222       99.182       99.222       103.18       107.58
       111.94       116.78       116.78       111.94            0            0
        122.1            0            0            0            0            0

Is this what you want?

Best Answer

Related Solutions

MATLAB: Add a value to an element in a matrix

MATLAB: How to display averages in new array

Related Question