MATLAB: A point charge of Q = 5 nC is located at (2,2,8). how to find the distance of the electric fields generated by the charge over the range of 0 < x < 4 m, 0 < y < 4 m, and 0 < z < 4 m due to the point charge

electric_field

x = 0:0.1:4;
y = 0:0.1:4;
z = 0:0.1:4;
%distance from Q to position of Efield
r = (((x-2).^2)+((y-2).^2)+((z-8).^2)).^0.5;

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>> [xA,yA,zA] = ndgrid(x,y,z);
>> rA = sqrt( (xA-2).^2 + (yA-2).^2 + (zA-8).^2 );

Of course rA will actually have size numel(x)*numel(y)*numel(z)

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MATLAB: Trying to produce a 4×40 table with the values of M, T, p, A.

Try this:

% Constants
gamma = 1.27;
x = (gamma - 1)/(gamma + 1);
% Initial Guesses
T = 1;
p = 1;
A = 10;
M = 0:.05:2
   % Loop starts here
for i=1:numel(M) 
%you should index the variable in order to save them in each iterations to avoid overwriting. 
      T(i) = (1-x)./((1+(x.*((M(i).^2)-1))));
      p(i) = (T(i)).^((x+1)./(2.*x));
      A(i) = ((1+x.*((M(i).^2)-1)).^(1/(2.*x)))./(M(i));
      fprintf('M %d: T=%.20f, p=%.20f\n, A=%.20f\n', M(i), T(i), p(i), A(i));
end
Table = table(M',T',p',A','variablenames',{'M','T','p','A'})

MATLAB: Charge simulation method

f=[1 2 3];
g=bsxfun(@minus,f,f.')

The other question depends on how you plot it and how do you want to choose the point.

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MATLAB: Trying to produce a 4×40 table with the values of M, T, p, A.

MATLAB: Charge simulation method

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