There are two matrix.
A = [1 4 3 4 56 6 8 9 11 2 1 4 58 1 2 1 59 1 9 2 28 8 1 6 4];
B = [1 2 9 2 5];
How can I minus each row of Matrix A by B to get C? The result C =
[0 2 -6 2 05 4 -1 7 -40 0 -8 2 07 -1 -7 -1 08 -1 0 0 -37 6 -8 4 -1] I know I can do a loop. But is there an easier way? Any suggestion would be appreciated!
The loop is:
m = size(A);for i = 1 :length(A) for n = 1:m(1) C(n,i) = A(n,i) - B(i); endend
Best Answer